1 kgf·m = 7.233 ft·lb/s
1 ft·lb/s = 0.138 kgf·m
Example:
Convert 15 Kilogram-Force Meter to Foot-Pound per Second:
15 kgf·m = 108.495 ft·lb/s
| Kilogram-Force Meter | Foot-Pound per Second |
|---|---|
| 0.01 kgf·m | 0.072 ft·lb/s |
| 0.1 kgf·m | 0.723 ft·lb/s |
| 1 kgf·m | 7.233 ft·lb/s |
| 2 kgf·m | 14.466 ft·lb/s |
| 3 kgf·m | 21.699 ft·lb/s |
| 5 kgf·m | 36.165 ft·lb/s |
| 10 kgf·m | 72.33 ft·lb/s |
| 20 kgf·m | 144.66 ft·lb/s |
| 30 kgf·m | 216.99 ft·lb/s |
| 40 kgf·m | 289.32 ft·lb/s |
| 50 kgf·m | 361.65 ft·lb/s |
| 60 kgf·m | 433.98 ft·lb/s |
| 70 kgf·m | 506.31 ft·lb/s |
| 80 kgf·m | 578.64 ft·lb/s |
| 90 kgf·m | 650.97 ft·lb/s |
| 100 kgf·m | 723.3 ft·lb/s |
| 250 kgf·m | 1,808.251 ft·lb/s |
| 500 kgf·m | 3,616.501 ft·lb/s |
| 750 kgf·m | 5,424.752 ft·lb/s |
| 1000 kgf·m | 7,233.003 ft·lb/s |
| 10000 kgf·m | 72,330.029 ft·lb/s |
| 100000 kgf·m | 723,300.291 ft·lb/s |
The Kilogram Force Meter (kgf·m) is a unit of torque that expresses the rotational force applied at a distance from a pivot point. This tool is essential for engineers, mechanics, and anyone involved in fields requiring precise calculations of torque. By converting various units of torque, users can ensure accuracy in their projects, whether they are designing machinery or performing routine maintenance.
The kilogram force meter (kgf·m) is defined as the torque resulting from a force of one kilogram-force applied perpendicularly to a lever arm that is one meter long. This unit is commonly used in mechanical engineering and physics to quantify rotational forces.
The kilogram force meter is part of the metric system, which is standardized globally. It is essential for ensuring consistency in measurements across different applications and industries. The kgf·m is often used alongside other torque units such as Newton meters (Nm) and foot-pounds (ft·lb).
The concept of torque has been around since the early days of mechanics, but the kilogram force meter became widely recognized in the 20th century with the advancement of engineering practices. Its use has evolved alongside technology, becoming a standard measurement in various fields, including automotive engineering and machinery design.
To illustrate the use of the kilogram force meter, consider a scenario where a force of 5 kgf is applied at the end of a lever arm that is 2 meters long. The torque can be calculated as follows:
[ \text{Torque (kgf·m)} = \text{Force (kgf)} \times \text{Distance (m)} ] [ \text{Torque} = 5 , \text{kgf} \times 2 , \text{m} = 10 , \text{kgf·m} ]
The kilogram force meter is widely used in various applications, including:
To effectively use the Kilogram Force Meter tool on our website, follow these steps:
What is the Kilogram Force Meter (kgf·m)?
How do I convert kgf·m to other torque units?
What is the significance of torque in engineering?
Can I use this tool for automotive applications?
Is the kilogram force meter standardized?
For more information and to access the tool, visit our Kilogram Force Meter Converter. By utilizing this tool, you can enhance your calculations and ensure precision in your projects.
The foot-pound per second (ft·lb/s) is a unit of power that quantifies the rate at which work is done or energy is transferred. Specifically, it measures the energy expended when one foot-pound of work is performed in one second. This unit is commonly used in engineering and physics to express mechanical power, particularly in the context of torque and rotational systems.
The foot-pound per second is part of the Imperial system of measurements, which is primarily used in the United States. It is defined as the power required to move one pound a distance of one foot in one second. This unit is often compared to other power units such as watts, where 1 ft·lb/s is approximately equal to 1.35582 watts.
The concept of measuring power dates back to the late 18th century when Scottish engineer James Watt introduced the term "horsepower" to describe the output of steam engines. The foot-pound per second emerged as a practical unit for measuring power in mechanical systems, especially in the context of engines and machinery.
To understand how to use the foot-pound per second, consider an example where a motor exerts a torque of 10 ft·lb at a rotational speed of 100 revolutions per minute (RPM). To calculate the power output in ft·lb/s, you can use the formula:
[ \text{Power (ft·lb/s)} = \frac{\text{Torque (ft·lb)} \times \text{RPM} \times 2\pi}{60} ]
In this case:
[ \text{Power} = \frac{10 \times 100 \times 2\pi}{60} \approx 104.72 \text{ ft·lb/s} ]
The foot-pound per second is widely used in various fields, including mechanical engineering, automotive engineering, and physics. It helps engineers and technicians assess the performance of engines, motors, and other machinery by providing a clear understanding of power output.
To interact with the foot-pound per second tool on our website, follow these steps:
What is the foot-pound per second (ft·lb/s)?
How do I convert foot-pounds per second to watts?
What is the significance of using ft·lb/s in engineering?
Can I use this tool for other units of power?
Is there a formula to calculate power using torque and RPM?
By utilizing the foot-pound per second tool effectively, users can enhance their understanding of power measurements and improve their engineering projects. For more information and to access the tool, visit Inayam's Torque Converter.
Inayam ![The Psychology of Money [Paperback] Morgan Housel](/_next/image?url=https%3A%2F%2Fm.media-amazon.com%2Fimages%2FI%2F81Dky%2BtD%2BpL._SY522_.jpg&w=1080&q=75)
