1 gf·cm = 7.2330e-5 ft·lb
1 ft·lb = 13,825.516 gf·cm
Example:
Convert 15 Gram-Force Centimeter to Foot-Pound:
15 gf·cm = 0.001 ft·lb
| Gram-Force Centimeter | Foot-Pound |
|---|---|
| 0.01 gf·cm | 7.2330e-7 ft·lb |
| 0.1 gf·cm | 7.2330e-6 ft·lb |
| 1 gf·cm | 7.2330e-5 ft·lb |
| 2 gf·cm | 0 ft·lb |
| 3 gf·cm | 0 ft·lb |
| 5 gf·cm | 0 ft·lb |
| 10 gf·cm | 0.001 ft·lb |
| 20 gf·cm | 0.001 ft·lb |
| 30 gf·cm | 0.002 ft·lb |
| 40 gf·cm | 0.003 ft·lb |
| 50 gf·cm | 0.004 ft·lb |
| 60 gf·cm | 0.004 ft·lb |
| 70 gf·cm | 0.005 ft·lb |
| 80 gf·cm | 0.006 ft·lb |
| 90 gf·cm | 0.007 ft·lb |
| 100 gf·cm | 0.007 ft·lb |
| 250 gf·cm | 0.018 ft·lb |
| 500 gf·cm | 0.036 ft·lb |
| 750 gf·cm | 0.054 ft·lb |
| 1000 gf·cm | 0.072 ft·lb |
| 10000 gf·cm | 0.723 ft·lb |
| 100000 gf·cm | 7.233 ft·lb |
The gram force centimeter (gf·cm) is a unit of torque that represents the rotational force applied at a distance of one centimeter from a pivot point. It is derived from the force exerted by one gram of mass under standard gravity (approximately 9.81 m/s²) acting at a distance of one centimeter from the axis of rotation. This unit is particularly useful in various engineering and physics applications where precise torque measurements are essential.
The gram force centimeter is part of the centimeter-gram-second (CGS) system of units. While the metric system has evolved, the CGS system remains relevant for certain scientific and engineering contexts. The standardization of this unit allows for consistent measurements across various applications, ensuring accuracy and reliability in calculations.
The concept of torque has been utilized since ancient times, but the formalization of units like the gram force centimeter emerged in the 19th century with the development of the CGS system. As engineering and scientific disciplines advanced, the need for precise torque measurements led to the adoption of various units, including the gram force centimeter, which remains in use today alongside the more commonly known Newton-meter (N·m) in the International System of Units (SI).
To illustrate how to calculate torque in gram force centimeters, consider a scenario where a force of 5 grams is applied at a distance of 10 centimeters from the pivot point. The torque can be calculated using the formula:
[ \text{Torque (gf·cm)} = \text{Force (g)} \times \text{Distance (cm)} ]
In this case:
[ \text{Torque} = 5 , \text{g} \times 10 , \text{cm} = 50 , \text{gf·cm} ]
The gram force centimeter is widely used in fields such as mechanical engineering, physics, and robotics. It is particularly valuable in applications involving small-scale mechanisms, where precise torque measurements are critical for performance and safety.
To effectively use the gram force centimeter tool on our website, follow these steps:
What is the gram force centimeter (gf·cm)?
How do I convert gram force centimeters to other torque units?
What are the applications of gram force centimeters?
How can I ensure accurate torque calculations?
Where can I find more information on torque measurements?
By utilizing the gram force centimeter tool effectively, you can enhance your understanding of torque measurements and apply this knowledge in various scientific and engineering contexts.
The foot-pound (ft·lb) is a unit of torque commonly used in the United States and the British Imperial system. It represents the amount of rotational force applied at a distance of one foot from the pivot point. This measurement is crucial in various fields, including engineering, automotive, and construction, where precise torque specifications are essential for safety and performance.
The foot-pound is standardized in the context of the Imperial system, where one foot-pound is defined as the torque resulting from a force of one pound applied perpendicularly at a distance of one foot from the axis of rotation. This unit is widely accepted in both professional and everyday applications, making it a reliable choice for torque calculations.
The concept of torque has been around for centuries, with its roots traceable to ancient mechanics. The foot-pound as a unit gained prominence during the Industrial Revolution, where the need for precise measurements in machinery and engineering became paramount. Over time, the foot-pound has evolved, but its fundamental definition remains unchanged, continuing to serve as a vital tool for professionals across various industries.
To illustrate the use of the foot-pound, consider a scenario where a wrench applies a force of 20 pounds at a distance of 2 feet from the pivot point. The torque can be calculated as follows: [ \text{Torque (ft·lb)} = \text{Force (lb)} \times \text{Distance (ft)} ] [ \text{Torque} = 20 , \text{lb} \times 2 , \text{ft} = 40 , \text{ft·lb} ]
The foot-pound is extensively utilized in various applications, including:
To use the Foot-Pound Unit Converter tool effectively, follow these steps:
What is the conversion of 100 foot-pounds to newton-meters?
How do I calculate torque using foot-pounds?
Is foot-pound the same as pound-force?
When should I use foot-pounds instead of newton-meters?
Can I convert foot-pounds to other torque units?
For more information and to access the Foot-Pound Unit Converter, visit Inayam's Torque Converter. By utilizing this tool, you can ensure accurate torque measurements, enhancing your projects' safety and effectiveness.
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